Question

PLEASE HELP!!!!

Answer 1

Answer:

Option A and C.

Step-by-step explanation:

Consider the below figure attached with this question.

The given expression is

$3^{\frac{4}{7}}$

The properties of exponent:

$(a^m)^n=a^{mn}$

$\sqrt[n]{x}=x^{\frac{1}{n}}$

Using these properties simplify all expression.

$(\sqrt[7]{3})^4=(3^{\frac{1}{7}})^4=3^{\frac{4}{7}}$

$\sqrt[4]{21}=21^{\frac{1}{4}}\neq 3^{\frac{4}{7}}$

$\sqrt[7]{81}=\sqrt[7]{3^4}=(3^4)^{\frac{1}{7}}=3^{\frac{4}{7}}$

$\sqrt[4]{3^7}=(3^7)^{\frac{1}{4}}=3^{\frac{7}{4}}\neq 3^{\frac{4}{7}}$

$\sqrt[7]{12}=12^{\frac{1}{7}}\neq 3^{\frac{4}{7}}$

$(\sqrt[4]{3})^7=(3^{\frac{1}{4}})^7=3^{\frac{7}{4}}\neq 3^{\frac{4}{7}}$

Therefore, the correct options are A and C.

Answer 2

Answer:

I don't think any of them are