Answer:
Step-by-step explanation:
Given that the null and alternate hypotheses are:
H0: μ1 ≤ μ2
H1: μ1 > μ2
Group Group One Group Two
Mean 112.00 97.00
SD 9.00 12.00
SEM 1.67 3.10
N 29 15
The mean of Group One minus Group Two equals 15.00
a) df = 42
standard error of difference = 3.212
b) Reject H0 if t statistic >1.302
t = 4.6699
Since t > 1.302, we reject null hypothesis
It is evident that the mean I is greater than mean 2.
