Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
2 answers:
S<span>ummation notation to write the series 49 + 54 + 59 +... for 14 terms is attached .
I hope that will help.
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Answer:
Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.
it is given by: where a is the first term , n is the number of term and d is the common difference.
Given the series:
here, Common difference(d) = 5
First term(a) = 49
by definition we have;
For nth term
= 5n + 44
To write the series using summation notation for 14 terms
Summation symbol
The series for 14th terms is given by;
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C is the answer for the question
Answer:
54
Step-by-step explanation:
3.1 2 6 divided by 2 2 = 2 (6 - 2) = 2 4. Dividing exponents : 3.2 5 6 divided by 5 2 = 5 (6 - 2) = 5 4
Answer:
Step-by-step explanation:
The zeros are the values of x for which y = 0
Quadratic formula
x = [5 ± √(5² – 4·1·6)] / [2·1]
= [5 ± √1] / 2
= [5 ± 1] /2
= 2, 3
sum of zeros = 5
Answer: y=-5/2x-4
Step-by-step explanation: Use the slope formula and slope-intercept form y=mx+b to find the equation.
Hope this helps you out! ☺