❣ [̲̅R̲̅][̲̅e̲̅][̲̅f̲̅][̲̅e̲̅][̲̅r̲̅]
[̲̅T̲̅][̲̅h̲̅][̲̅e̲̅]
[̲̅A̲̅][̲̅t̲̅][̲̅t̲̅][̲̅a̲̅][̲̅c̲̅][̲̅h̲̅][̲̅m̲̅][̲̅e̲̅][̲̅n̲̅][̲̅t̲̅] ❣
❣❣... ℏ✺℘ḙ !т ℏḙℓ℘ṧ ʏ✺ṳ...❣❣
Chun wants to <span>reduce the weight of garbage produced to 85% of the weight produced this month.
This means that, Chun's garbage weight next month should be equal to 85% of his garbage weight this month.
Translating this into an equation, we will find that:
garbage weight next month = 85% of garbage weight this month
garbage weight next month = 0.85 * garbage weight this month
garbage weight next month = 0.85*690
garbage weight next month = 586.5 pounds
Based on the above calculations, his target weight for the garbage next month is </span>586.5 pounds
Answer:
The parametric equations for the tangent line are
:
x = Cos(10) - t×Sin(10)
y = Sin(10) + t×Cos(10)
z = 20 + 2t
Step-by-step explanation:
When Z=20:
Z=2t=20 ⇒ t=10
The point of tangency is:
r(10)= Cos(10) i + Sin(10) j + 20 k
We have to find the derivative of r(t) to get the tangent line:
r'(t)= -Sin(t) i + Cos(t) j + 2 k
The direction vector at t=10 is:
r'(10)= -Sin(10) i + Cos(10) j + 2 k
So, the equation of the tangent line is given by:
x = cos 10 -t×Sin(10)
y = sin 10 + t×Cos(10)
z = 20 + 2t
6(a+3) = 18 + 6a
6(a+3)=6(3+a)
a+3=3+a
a-a=3-3
0a=0
<span>B. all real numbers</span>
