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gogolik [260]
3 years ago
6

Which can be used to expand the expression below?

Mathematics
1 answer:
musickatia [10]3 years ago
7 0
What is the question 
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What is -4(x + 9) combine like terms
yKpoI14uk [10]

Answer:

-4x-36

Step-by-step explanation:

multiply -4 by x

multiply -4 by 9 and add each together

6 0
3 years ago
Read 2 more answers
Seven friends bought pizza. Each friend pitched in the same amount. If the pizza came to a total of $14.49, how much did each fr
Svet_ta [14]
Each friend payed $2.07
8 0
3 years ago
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Diego is 165 cm tall. Andre is 1.7 m tall. Who is taller, Diego or Andre? 1 m = 100 cm.
mart [117]

Answer:

Diego

Step-by-step explanation:

Diego is because 1m = 100 and Diego is 165 and that is alote bigger from 1.7.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7Bx%5E%7B2%7D-8x%2B8%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\in
12345 [234]

Answer:

{ \underline{ \sf{\int\limits^2_1 {x^{2}-8x+8 } \, dx}  \: =  \:  - 1}}

Step-by-step explanation:

{ \tt{\int\limits^2_1 {x^{2}-8x+8 } \, dx}} \\  \\ =  { \tt{[ \frac{ {x}^{3} }{3}  - 4 {x}^{2}  + 8x ] {}^{2} _{1}}}

Substitute x with the limits:

= { \tt{( \frac{ {2}^{3} }{3}  - 4( {2)}^{2} + 8(2)) - ( \frac{ {1}^{3} }{3}  - 4( {1)}^{2}  + 8(1)) }} \\  = { \tt{( \frac{8}{3}  -  \frac{11}{3} )}} \\  \\  = { \tt{ - 1}}

4 0
3 years ago
What is the domain of the relation?
amm1812

Domain:

{-4, -2, -1 , 1, 4}


Hope it helps

3 0
4 years ago
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