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ipn [44]
4 years ago
9

A sprinter knows that starting with an initial burst of speed gives her a velocity over time, t, of v(t) = 3.5t + 0.25t2 meters

per second. If she saves her energy for the end of the race, she runs with a velocity of v(t) = 1.2t + 0.03t2. Which strategy will cover the greatest distance in a given time?
Mathematics
1 answer:
Luda [366]4 years ago
4 0
To solve the question we proceed as follows:
Distance is the integral of the velocity. Thus given:
v(t)=3.5t+0.25t^2
d(t)=1.75t^2+0.08333t^3.....i

v(t)=1.2t+0.03t^2
d(t)=0.6t^2+0.01t^3.......ii

From equation i and ii, we conclude that using strategy i will cover greater distance
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3.3 multiply 2.5+ 5.7 multiply 2.5<br> solve it please
Amiraneli [1.4K]

Answer:

22.50

Step-by-step explanation:

3.3*2.5+5.7*2.5=

8.25. +.  14.25=22.50

plz mark me Brainliest

7 0
3 years ago
(05.06)A chocolate bar measures 40 mm wide, 80 mm long, and 5 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper
photoshop1234 [79]

Answer:

Will’s Wrapping Company needs 7,720 mm2 of paper to wrap the chocolate bar.

Step-by-step explanation:

we know that

The amount of paper needed to make the wrapper is equal to the surface area of the chocolate bar

The surface area of a rectangular prism (chocolate bar) is equal to

SA=2B+PH

where

B is the area of the base

P is the perimeter of the base

H is the height of he prism

In this problem we have

L=80\ mm\\W=5\frac{1}{2}\ mm=5.5\ mm\\H=40\ mm

<em>Find the area of the base</em>

B=LW=(80)(5.5)=440\ mm^2

<em>Find the perimeter of the base</em>

P=2(L+W)=2(80+5.5)=171\ mm

<em>Find the surface area</em>

SA=2(440)+171(40)\\SA=7,720\ mm^2

5 0
3 years ago
camp oak gets 32 boxes of orange juice and 56 boxes of apple juice each self in the cupboard can hold 8 boxes of  juice what is
Flura [38]
32 boxes of oj + 56 boxes of aj = 90 boxes of juice
If a self can only hold 8 boxes of juice, then you need to divide 90 by 8.
90/8 = 11.25
This means that they need at least 12 shelves for all the Juice boxes.
7 0
3 years ago
A couple realizes a real estate financing of R $ 180,000.00, to be paid in 360 monthly installments, with an effective interest
Lilit [14]

Answer:

ANSWER: letter D

Step-by-step explanation:

In the tenth installment, the debit balance is, in reais, of

180000 - 9. 500 = 175500

The 1% interest on this amount results in:

1% . 175 500 = 1755

Thus, the tenth installment is, in reais, 500 + 1755 = 2255

8 0
3 years ago
The mean weight of an adult is 69 kilograms with a variance of 121. If 31 adults are randomly selected, what is the probability
amid [387]

Answer:

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Also, important to remember that the standard deviation is the square root of the variance.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 69, \sigma = \sqrt{121} = 11, n = 31, s = \frac{11}{\sqrt{31}} = 1.97565

What is the probability that the sample mean would be greater than 70.5 kilograms?

This is 1 subtracted by the pvalue of Z when X = 70.5. So

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{70.5 - 69}{1.97565}

Z = 0.76

Z = 0.76 has a pvalue of 0.7764

1 - 0.7764 = 0.2236

0.2236 = 22.36% probability that the sample mean would be greater than 70.5 kilograms.

8 0
3 years ago
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