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harkovskaia [24]
4 years ago
13

What is the solution of the following system?

Mathematics
1 answer:
alexandr402 [8]4 years ago
5 0
<span>4x-y = 15 3x+2y = -8 Multiplying the first equation by two makes for an easy elimination of the y variable. 8x - 2y = 30 3x + 2y = -8 Add vertically. 11x = 22. Divide by 11 on both sides and get x = 2. Plug into an equation. 4(2) - y = 15 8 - y = 15 8 = 15 + y 8 - 15 = y -7 = y. Thus the solution is indeed (2, -7).</span>
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3 years ago
50 points.
Sphinxa [80]

Answer:

1

Step-by-step explanation:

Using the rules of exponents

(a^m)^{n} = a^{mn}

a^{m} × a^{n} = a^{(m+n)}

Given

(\frac{1}{x^{(a-b)}) } ^{a+b} × (\frac{1}{x^{b+a}) } ^{b-a}

= \frac{1}{x^{(a-b)(a+b)} } × \frac{1}{x^{(b+a)(b-a)} }

= \frac{1}{x^{(a^2-b^2)} } × \frac{1}{x^{(b^2-a^2)} }

= \frac{1}{x^{(a^2-b^2+b^2-a^2)} }

= \frac{1}{x^{0} }

= \frac{1}{1}

= 1

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