Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
Answer:31
Step-by-step explanation:
Answer:
The line equation that passes through the given points is 5x – 2y + 16 = 0
Explanation:
Given:
Two points are A(-2, 3) and B(0, 8).
To find:
The line equation that passes through the given two points.
Solution:
We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by
.............(1)
here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.
Now substitute the values in (1)
2y – 16 = 5x
5x – 2y + 16 = 0
Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.
