Answer: length = 8 units
Width = 2 units
Step-by-step explanation:
Let the length of the rectangle be represented by L
Let the width of the rectangle be represented by W
The sum of 5 times the width of a rectangle and twice its length is 26 units. This means that
5W + 2L = 26 - - - - - - - - 1
The difference of 15 times the width and three times the length is 6 units. It means that
15W - 3L = 6 - - - - - - - - 2
The system equations are equation 1 and equation 2.
Multiplying equation 1 by 3 and equation 2 by 2, it becomes
15W + 6L = 78
30W - 6L = 12
Adding both equations,
45W = 90
W = 90/45 = 2
15W - 3L = 6
15×2 - 3L = 6
-3L = 6 - 30 = - 24
L = - 24/ -3 = 8
Im not for sure but i would say 2003-01-01-00-00-00_files
Answer:
A quick hack is often to partially express some function in terms of a Taylor approximation about x0, since higher order terms of x go to zero if we are considering limits for (x−x0)→0. To really answer your question we need to know what the original question was, that is, about which point do you want the expansion? Let us assume around 0. Then we have the Maclaurin series:
cos(x)=1−12x2+O(x4)
You can add more terms if you need to. Now we write:
ln(1+(−12x2))=…
Do you know the standard Maclaurin series for this function?
Hint: it is of the form ln(1+u)
Step-by-step explanation:
<span>The critical value will be established. This is the point at which the researcher can reject the null hypothesis because the value falls outside the bounds at which the result was due to random chance. Values inside this bound show that the result cannot be determined to be due to the variables, so they cannot be used to reject the null hypothesis.</span>
