Hello :
x²-8x+15 = (x-3)(x-5)
<span>h(x) = f(x) ÷g(x) = (x-3)(x-5)/(x-3)= x-5</span>
Step-by-step explanation:
![\begin{array}{c|cc}\cline{2-3} 5 & 225 & 625 \\ \cline {2-3} 5 & 45 & 125 \\ \cline {2-3} 5 & 9 &25 \\ \cline {2,3} 5 & 9 & 5 \\ & 9 & 1\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Ccc%7D%5Ccline%7B2-3%7D%205%20%26%20225%20%26%20625%20%5C%5C%20%5Ccline%20%7B2-3%7D%205%20%26%2045%20%26%20125%20%5C%5C%20%5Ccline%20%7B2-3%7D%205%20%26%209%20%2625%20%5C%5C%20%5Ccline%20%7B2%2C3%7D%205%20%26%209%20%26%205%20%5C%5C%20%26%209%20%26%201%5Cend%7Barray%7D)
LCM=5×5×5×5×9=5625
Answer:-9.
Step-by-step explanation: The actual answer is 10 7/10...
The closest estimate therefore is -9
Answer:
The vector equation in terms of v1 and v2 is x₁v₁ +x₂v₂ = [296 2454]
Step-by-step explanation:
Solution
The aim is to write down a vector equation in terms of v1 and v2, when solution gives the number of days each mine should operate in order to produce 296 tons of copper and 2454 kilograms of silver.
Thus,
Suppose that b = [ 296 2454] is the corresponding vector which is representing the total needed output.
Now,
If the company operates mine 1 for x1 days and mine #2 for x2 days
Then,
The total output becomes x₁v₁ +x₂v₂ which is the same output to b = [296 2454]
Hence, x₁ and x₂ should be satisfactory to the needed vector equation x₁v₁ +x₂v₂ = [296 2454]
So, the vector equation becomes x₁v₁ +x₂v₂ = [296 2454]
What you need to do is subtract 2 hours and 48 minutes from 4 hours and 25 minutes. Each hour is 60 minutes. 2 hrs and 48 min is 168 minutes, and 4 hrs and 25 min is 265 minutes. 265 subtract 168 is 97. That means the kids spent 1 hour and 37 minutes at the pool in the afternoon.