Question

F(x) = x2 − 8x + 15 g(x) = x − 3 h(x) = f(x) ÷g(x)

Answer 1

Hello : 
x²-8x+15 = (x-3)(x-5)
h(x) = f(x) ÷g(x) = (x-3)(x-5)/(x-3)= x-5

Answer 2

Answer:

Step-by-step explanation:

Given: It is given that $f(x)=x^2-8x+15$ and $g(x)=x-3$.

To find: The value of $h(x)=\frac{f(x)}{g(x)}$

Solution: It is given that $f(x)=x^2-8x+15$ and $g(x)=x-3$, then the value of $h(x)=\frac{f(x)}{g(x)}$ will be:

$h(x)=\frac{x^2-8x+15}{x-3}$

$h(x)=\frac{x^2-5x-3x+15}{x-3}$

$h(x)=\frac{x(x-5)-3(x-5)}{(x-3)}$

$h(x)=\frac{(x-3)(x-5)}{(x-3)}$

$h(x)=x-5$

Thus, the value of $h(x)$ will be $x-5$.