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3 years ago

What would be the next number in the pattern 1/324, 1/108 , 1/36 , 1/12 ,

1 answer:

6 0

The Denominator in This Pattern Is Always Being Divided By 3, So:
1/(12/3) = Next Number
12/3 = 4.
So, The Next Number Is:
1/4

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Question 1 (Essay Worth 10 points)

il63 [147K]

Answer:

Part A. x = 1/26 Part B. x = 1/50

Step-by-step explanation:

Solve for x:

26 x = 1

Divide both sides by 26:

Answer: x = 1/26

___________________

Solve for x:

50 x = 1

Divide both sides by 50:

Answer: x = 1/50

8 0

3 years ago

On the first day of a road trip, Roberto traveled 213 miles from home. On the second day, he drove 149 miles farther. How many m

jek_recluse [69]

The answer would be 362 miles

add the number of miles from day one and day two

4 0

3 years ago

Please help me with this question. i would really appreciate it!

NemiM [27]

Answer:

it should be c or d

Step-by-step explanation:

5 0

3 years ago

the high school debate team is developing a logo to represent their club. A scale drawing of the logo design is presented below,

Fantom [35]

Answer:

The enlargement will be 25 times and the enlargement area will be $2250 \text{ inches}^2$ .

Step-by-step explanation:

It is given that each grid unit is equal to 3 inches. SO we have to use this scale.

The total height of the scale drawing is 21 inch and the enlargement has a height given as 105 inches. Therefore it has scale factor of 5. It means that each dimension is enlarged by 5 times the dimension in the scale drawing. So the enlargement of the logo will be 25 times and the enlargement area will be 2250 square inches.

7 0

3 years ago

An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that

3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0

3 years ago