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3 years ago

Write the answer in numeric form?

Mathematics

1 answer:

kondor19780726 [428]3 years ago

8 0

Answer:

x=11. 38 degrees; 52 degrees

Step-by-step explanation:

90+6x-14+3x+5=180

81+9x=180

9x=99

x=11

38 degrees, 52 degrees

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What is the value of X?

Pavel [41]

Step-by-step explanation:

$x = 2 \times 52.5 \degree \\ x = 105 \degree$

4 0

3 years ago

Read 2 more answers

What is <img src="https://tex.z-dn.net/?f=1895%20%5Ctimes%20906" id="TexFormula1" title="1895 \times 906" alt="1895 \times 90

netineya [11]

Answer:

1895 x 906=

1,716,870

4 0

3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago

0.2(10-5c)=5c-16 halp

iogann1982 [59]

Answer:

c= 3

Step-by-step explanation:

0.2(10 -5c)= 5c -16

Expand:

0.2(10) +0.2(-5c)= 5c -16

2 -c= 5c -16

Bring all c terms to 1 side, constant to the other:

5c +c= 2 +16

Simplify:

6c= 18

Divide by 6 on both sides:

c= 18 ÷6

c= 3

5 0

3 years ago

Read 2 more answers

Solve for b. 4/3b+2=4-1/3b

Maksim231197 [3]

Answer:

b = $\frac{6}{5}$

Step-by-step explanation:

Multiply through by 3 to clear the fractions.

4b + 6 = 12 - b ( add b to both sides )

5b + 6 = 12 ( subtract 6 from both sides )

5b = 6 ( divide both sides by 5 )

b = $\frac{6}{5}$

4 0

3 years ago