Question

In algibratic fractions what is 1/2x-1/3y

Answer 1

 1  - 1  = 1(2x)(3y) - 1(2x)(3y) = 6xy - 6xy = 0 
2x   3y     (2x)(3y)     (2x)(3y)     6xy    6xy  6xy

Answer 2

Simplify each term.

1/2X - 1/3Y

Combine 1/2x and −1/3y using a common denominator.

To write −1/3y as a fraction with a common denominator, multiply by 2x/2x. 

(1 / 2x )(3y / 3y) + (−1 / 3y) (2x / 2x) 

Write each expression with a common denominator of 6xy, by
multiplying each by an appropriate factor of 1. 

1 (3y)/6xy − 1 (2x)/6xy 

Combine the numerators over the common denominator. 

1(3y) − (1(2x))/6xy

Simplify the numerator.

3y−(1(2x))/6xy 

Simplify. 

3y−(2x)/6xy

3y−2x/6xy

Simplify with factoring out.

Reorder 3y and −2x. 

−2x+3y/6xy 

Factor −1 out of −2x. 

−1(2x)+3y/6xy 

Factor −1 out of 3y. 

−1(2x)−1(−3y)/6xy 

Factor −1 out of −1(2x)−1(−3y). 

−1(2x−3y)/6xy

Move the negative in front of the fraction. 

−2x−3y/6xy