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baherus [9]
3 years ago
13

In algibratic fractions what is 1/2x-1/3y

Mathematics
2 answers:
kari74 [83]3 years ago
7 0
<u> 1 </u> -<u> 1  </u>= <u>1(2x)(3y)</u> - <u>1(2x)(3y)</u> = <u>6xy</u> - <u>6xy</u> = <u>0  </u>
2x   3y     (2x)(3y)     (2x)(3y)     6xy    6xy  6xy
Doss [256]3 years ago
5 0
Simplify each term.

1/2X - 1/3Y

Combine 1/2x and −1/3y using a common denominator.

To write −1/3y as a fraction with a common denominator, multiply by 2x/2x. 

(1 / 2x )(3y / 3y) + (−1 / 3y) (2x / 2x) 

Write each expression with a common denominator of 6xy, by
multiplying each by an appropriate factor of 1. 

1 (3y)/6xy − 1 (2x)/6xy 

Combine the numerators over the common denominator. 

1(3y) − (1(2x))/6xy

Simplify the numerator.

3y−(1(2x))/6xy 

<span>Simplify. 

</span>3y−(2x)/6xy

<span><span>3y−2x/</span><span>6xy</span></span>

Simplify with factoring<span> out.
</span>
Reorder <span>3y</span><span> and </span><span><span>−2x</span>.</span> 

<span><span>−2x+3y/</span><span>6xy</span></span><span> 
</span>
Factor <span>−1</span><span> out of </span><span><span>−2x</span>.</span> 

<span><span>−1(2x)+3y/</span><span>6xy</span></span> 

Factor <span>−1</span><span> out of </span><span><span>3y</span>.</span> 

<span><span>−1(2x)−1(−3y)/</span><span>6xy</span></span><span> 
</span>
Factor <span>−1</span><span> out of </span><span><span>−1(2x)−1(−3y)</span>.</span> 

<span>−1(2x−3y)/</span><span>6xy

</span>Move the negative in front of the fraction<span>. 
</span>
<span>−<span><span>2x−3y/</span><span>6xy</span></span></span><span>





</span>
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