Count the number of positive integers less than 100 that do not contain any perfect square factors greater than 1.
Possible perfect squares are the squares of integers 2-9.
In fact, only squares of primes need be considered, since for example, 6^2=36 actually contains factors 2^2 and 3^2.
Tabulate the number (in [ ])of integers containing factors of
2^2=4: 4,8,12,16,...96 [24]
3^2=9: 9,18,....99 [11]
5^2=25: 25,50,75 [3]
7^2=49: 49,98 [2]
So the total number of integers from 1 to 99
N=24+11+3+2=40
=>
Number of positive square-free integers below 100 = 99-40 = 59
I'm pretty sure the original price would be $90.75 because 3/4 is .75, so all you have to do is add that to the $90
Answer:
C=13
Step-by-step explanation:
Pythagorean theorem
a^2 + b^2=c^2
a squared plus b squared equals c squared
Answer:
$16.77
Step-by-step explanation:
6.99*2.4=16.776
The numbers are irrational, so they can't be exactly written down
using only digits.
In exact form, they are
1 + √57
and
1 - √57 .
In rounded form, they are
8.54983
and
-6.54983 .
