Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒ 
Now let 
∵ 
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
3x+2 mulitiply by 2. you will get 6x+4 now put 10x-12 like so 6x+4=10x-12. then use like terms and subtract 6x from 10x. you will get 4x-12=4. then add 12 to cancel out then divide 16 by 4 and then x=4 then plug in 4 to replace x in 3x+2.
The answer is 14
Answer:
Number of Favorable Outcomes over Total Number
Step-by-step explanation:
Answer: the answer is 16
Step-by-step- explanation:
Since the two sides of a triangle must be greater than the third we can take the sum of two smallest sides and add them together to equal 92. Meaning the length of the longest side MUST BE 91 feet so the amount of the remaining rope would equal to 107-91 and that’s where we get 16
5.7y-5.2=y/2.5
Add 5.2 to both sides:
5.7y = y/2.5 + 5.2
y/2.5 = 0.4y
5.7y = 0.4y + 5.2
Subtract 0.4y from both sides:
5.3y = 5.2
Divide both sides by 5.3:
y = 5.2/5.3
y = 0.98113