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3 years ago

Three vertices of a rectangle are given. Find the coordinates of the fourth vertex.

1 answer:

5 0

The distance between (2,5) and (6,1) is:

$\sf Distance = \sqrt{\left( 6 - 2 \right)^2 + \left( 1 - 5 \right)^2} \\\\ =\sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

The distance between the fourth vertex and (4,-1) should also be 4√2

The only point that gives us that distance is B. (0,3)

$\sf Distance = \sqrt{\left( 4 - 0 \right)^2 + \left( -1 - 3 \right)^2} \\ \\= \sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

Your final answer is B. (0,3)

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krok68 [10]

Answer:

Step-by-step explanation:

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3 years ago

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Lostsunrise [7]

Answer:

41 21/25

Step-by-step explanation:

38 1/25 + 3 4/5 = 41 21/25

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3 years ago

Read 2 more answers

Adriana va a llenar bolsas de dulces para su fiesta de cumpleanos si tiene un paquete con 100 paletas y otro con 56 chocolates y

lions [1.4K]

Answer:

56 bags of a chocolate and a popsicle

Step-by-step explanation:

The first thing is to find the relationship between the number of popsicles and the number of chocolates, which would be the quotient of these:

100/56 = 1.78

Since it does not reach number two, you cannot add 2 popsicles and 2 chocolates, therefore the only way that they contain the same amount is that there is a chocolate and a popsicle, that is to say that a total of 56 bags would come out.

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3 years ago

You are at a European beach with 60 other visitors. 36 of them speak English. If you randomly meet two people on the beach, what

Kaylis [27]

Answer:

Assuming I'm one of the 36 English speakers and the other 24 speak Spanish for illustration purposes. The problem can be modeled as 59 marbles with 35 E and 24 S marbles as N = 59 possible outcomes = n(E) + n(S) = 35 + 24.

So I reach into the pile of marbles (on the beach) and the probability that it's p(E) = n(E)/N = 35/59 = 0.593220339 when I meet the one person. ANS

I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three. This one is p(E >= 1|4 attempts). We can trace out a probability tree to identify those branches that contain at least one E event. So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619 ANS. In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

Step-by-step explanation:

3 0

3 years ago

The landing for the steps leading up to a county courthouse is shaped like a trapezoid. The area of the landing is 1500 square f

77julia77 [94]

Answer:

The length of the longer base is 80 feet.

Step-by-step explanation:

We are given that county courthouse is shaped like a trapezoid.

Let the height of the court house be h

Since we are given that The shorter base of the trapezoid is 15 feet longer than the height.

So, the shorter base = h+15