Question

Three vertices of a rectangle are given. Find the coordinates of the fourth vertex.

Answer 1

The distance between (2,5) and (6,1) is:

$\sf Distance = \sqrt{\left( 6 - 2 \right)^2 + \left( 1 - 5 \right)^2} \\\\ =\sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

The distance between the fourth vertex and (4,-1) should also be 4√2

The only point that gives us that distance is B. (0,3)

$\sf Distance = \sqrt{\left( 4 - 0 \right)^2 + \left( -1 - 3 \right)^2} \\ \\= \sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

Your final answer is B. (0,3)