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lys-0071 [83]
3 years ago
7

Three vertices of a rectangle are given. Find the coordinates of the fourth vertex.

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0
The distance between (2,5) and (6,1) is:

\sf Distance = \sqrt{\left( 6 - 2 \right)^2 + \left( 1 - 5 \right)^2} \\\\  =\sqrt{ 16 + 16} \\  \\ = \boxed{\bf{4 \sqrt{ 2 } }}

The distance between the fourth vertex and (4,-1) should also be 4√2

The only point that gives us that distance is B. (0,3)

\sf Distance = \sqrt{\left( 4 - 0 \right)^2 + \left( -1 - 3 \right)^2} \\ \\= \sqrt{ 16 + 16} \\  \\ = \boxed{\bf{4 \sqrt{ 2 } }}

Your final answer is B. (0,3)
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