Answer:
F=48
Step-by-step explanation:
see the explanation and workings in the picture above.
This should not be in the elementary school section I didn't even learn about this....
Answer: No, x+3 is not a factor of 2x^2-2x-12
========================================================
Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
----------------------------------------
Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer= 11. Two negatives equals a positive so you add them together.
Given the equqation
W = 2H + 13
where
W is the weight in lb
H is the height in inches
If the height of a person is 5 ft 6 in, we must first convert it to inches. So,
H = 5(12) + 6
H = 66 in
The body weight then is,
W = 2(66) + 13
W = 145 lbs
