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Serggg [28]
3 years ago
5

Laura is building a fence around her pond. The pond has a diameter of 5 ft. Which is the minimum amount of fence Laura will need

?
Mathematics
2 answers:
Maslowich3 years ago
6 0

Answer: The minimum amount of fence Laura will need is 15.70 ft.

Step-by-step explanation:

Hi, to answer this question we have to find the circumference of the pond.

The formula for the circumference (C) is:

C = π x d

Where "d" is the diameter.

Replacing with the values given:

C = π x 5 =15.70ft

The minimum amount of fence Laura will need is 15.70 ft.

Feel free to ask for more if needed or if you did not understand something.

aivan3 [116]3 years ago
3 0

Answer: 15.707 feet of fence.

Explanation: The formula to find this would be the one you’d use to find circumference, which is: C = 2(Pi)r

Half of the diameter is the radius, so plug that in and it becomes:

C = 2(pi)2.5

Then you just solve it and the result is C = 15.707

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z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936  

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Step-by-step explanation:

Information given

\bar X_{1}=7.6 represent the mean for Gibbs products

\bar X_{2}=8.1 represent the mean for the competitor

\sigma_{1}=2.3 represent the population standard deviation for Gibbs

\sigma_{2}=2.9 represent the sample standard deviation for the competitor

n_{1}=40 sample size for the group Gibbs

n_{2}=55 sample size for the group competitor

\alpha=0.05 Significance level provided

z would represent the statistic

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We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}< 0  

The statistic would be given by:

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

Replacing the info given we got:

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The p value can be founded with this formula:

p_v =P(z  

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

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