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IrinaVladis [17]
3 years ago
14

Ratio equivalent to 12:21 with greater terms

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
12:21 times 2 = 24:42       __                  __
                                                 \__(^ ^)__/           meh?
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Chris withdraws $7.50 per week from his savings account. After 15 weeks, the balance in the account is $585.
slava [35]
Y-585 = -7.5(x-15)

y = -7.5x - 7.5(-15) + 585
y = -7.5x + 697.50

C = -7.5(52) + 697.50 = $307.50
4 0
4 years ago
Ifangle1∠ 1 and angle2∠ 2 are complementary, find the measure of x and the measures of the angles when LaTeX: m\angle1=\left(6x+
Liono4ka [1.6K]

Answer:

<h3>x = 5</h3>

Step-by-step explanation:

The sum of two complementary angle is 90 degrees. Given the following complementary angles;

<1 = 6x + 5

<2 = 8x + 15

<1 + <2 = 90 (complementary angles)

6x + 5 + 8x + 15 = 90

14x + 20 = 90

14x = 90-20

14x = 70

x = 70/14

x = 5

Hence the measure of x is 5

6 0
3 years ago
Graph this equation on the coordinate plane.
Liula [17]
Select any two x and plug it into the equation to get the corresponding y:

I’ll do 1 and 2 for example.
x = 1
y = -2(1) + 4
y = -2 + 4
y = 2

So we have the point (1, 2)


x = 2
y = -2(2) + 4
y = -4 + 4
y = 0
We have the point (0, 2)

Plot (1, 2) and (0, 2) and draw the line that goes through both.
6 0
3 years ago
Read 2 more answers
By 8:00 a.M,, the snack bar had made 3,256 in sales. By noon the snack bar total sales were 8,821 About how much money did snack
marissa [1.9K]
5,565, if you subtract the 2 numbers
6 0
3 years ago
Consider an urn containing 8 white balls, 7 red balls and 5 black balls.
weqwewe [10]

Answer + Step-by-step explanation:

1) The probability of getting 2 white balls is equal to:

=\frac{8}{20} \times \frac{7}{19}\\\\= 0.147368421053

2) the probability of getting 2 white balls is equal to:

=C^{2}_{5}\times (\frac{8}{20} \times \frac{7}{19}) \times (\frac{12}{18} \times \frac{11}{17} \times \frac{10}{16})\\=0.397316821465

3) The probability of getting at least 72 white balls is:

=C^{72}_{150}\times \left( \frac{8}{20} \right)^{72}  \times \left( \frac{7}{20} \right)^{78}  +C^{73}_{150}\times \left( \frac{8}{20} \right)^{73}  \times \left( \frac{7}{20} \right)^{77}  + \cdots +C^{149}_{150}\times \left( \frac{8}{20} \right)^{149}  \times \left( \frac{7}{20} \right)^{1}  +\left( \frac{8}{20} \right)^{150}

=\sum^{150}_{k=72} [C^{k}_{150}\times  \left( \frac{8}{15} \right)^{k}  \times \left( \frac{7}{15} \right)^{150-k}]

5 0
1 year ago
Read 2 more answers
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