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ladessa [460]
3 years ago
5

How many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution infinite number of solut

ions.
Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

The system of equations has infinite solutions.

<h2>Given to us,</h2>
  • y=-6x+2
  • -12x-2y=-4

<h3>Equation 2,</h3>

The value of y is already given in equation 1,

-12x-2y=-4

substituting the value of y in equation 2,

-12x-2(-6x+2)=-4\\-12x +12x-4=-4\\-12x+12x=-4+4\\0=0

The solution of the two equations is 0. Also, we can see that both the equations are in ratio.

Further, the image also shows that the line of the two equations are coinciding.

Hence, the system of equations has infinite solutions.

Learn more about System of solutions:

brainly.com/question/14264175

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If y varies inversely with x and y =5 when x=20 find x when y = -4​
sweet-ann [11.9K]

Answer:

x=-25

Step-by-step explanation:

Inverse variation

xy =k

We know x and y

20*5 =k

100 =k

So the formula is

x y = 100

We know y = -4

x (-4) = 100

Divide each side by -4

-4x/-4 = 100/-4

x = -25

7 0
3 years ago
Solve the following system:
Angelina_Jolie [31]
You can rewrite the second equation because you know what y equals, so you can write it as 2x + x + 3 = 9
3x + 3 = 9
- 3
3x = 6
÷ 3
x = 2

And now you use the equation of what y equals and substitute in the value of x, so y = 2 + 3
y = 5

So your final answer is A. (2, 5). I hope this helps!
7 0
4 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
Draw to show 55 three different ways
MAXImum [283]
Needs more information.

6 0
4 years ago
Read 2 more answers
Since the hypotenuse has length 60, then the side adjacent to the 39° angle is given by
Evgesh-ka [11]

Answer:

x= 46.6 (3 s.f.)

Step-by-step explanation:

Please see the attached picture for full solution.

7 0
4 years ago
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