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ladessa [460]
2 years ago
5

How many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution infinite number of solut

ions.
Mathematics
1 answer:
Anna35 [415]2 years ago
3 0

The system of equations has infinite solutions.

<h2>Given to us,</h2>
  • y=-6x+2
  • -12x-2y=-4

<h3>Equation 2,</h3>

The value of y is already given in equation 1,

-12x-2y=-4

substituting the value of y in equation 2,

-12x-2(-6x+2)=-4\\-12x +12x-4=-4\\-12x+12x=-4+4\\0=0

The solution of the two equations is 0. Also, we can see that both the equations are in ratio.

Further, the image also shows that the line of the two equations are coinciding.

Hence, the system of equations has infinite solutions.

Learn more about System of solutions:

brainly.com/question/14264175

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kirza4 [7]

Answer:

yes,this is congruent by SAS criteria

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Explain why the overlapping powers caused conflict.
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5 0
3 years ago
Find the coordinate that divides the directed line segment from A(-2,-4) to B(8,1) in the ratio of 2 to 3
zalisa [80]
We have that
A(-2,-4)  B(8,1) <span>

let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3

we know that

A--------------M----------------------B
        2                     3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so

step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2

step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2

the coordinates of point M is (2,-2)

see the attached figure

7 0
3 years ago
Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.
Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

y=ax^2+bx+c

Here the vertex of an up - down facing parabola has a form of,

x_v=-\dfrac{b}{2a}

The parameters we have are,

a=-5,b=-10, c=6

Plug them in vertex formula,

x_v=-\dfrac{-10}{2(-5)}=-1

Plug in the x_v into the equation,

y_v=-5(-1)^2-10(-1)+6=11

We now got a point parabola vertex with coordinates,

(x_v, y_v)\Longrightarrow(-1,11)

From here we emerge two rules:

  • If a then vertex is max value
  • If a>0 then vertex is min value

So our vertex is minimum value since,

a=-5\Longleftrightarrow a

Hope this helps.

r3t40

7 0
3 years ago
Q4
SCORPION-xisa [38]

Answer:

A. 8cm^{3} B. Yes

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
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