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3 years ago

Math help 20 points and brainliest

Mathematics

1 answer:

Dima020 [189]3 years ago

6 0

Use distribution to find the answer to this one.

5x * 6x² = 30x^3

5x * 3x = 15x²

5x * 7 = 35x

-1 * 6x² = -6x²

-1 * 3x = -3x

-1 * 7 = -7

30x^3 + 15x² + 35x - 6x² - 3x - 7 → simplify this using like terms (look at the exponent of x and if there even is one)

30x^3 stays becuase there is no other like terms

15x² - 6x² = 9x² becuase they are like terms

35x - 3x = 32x because they are like terms

-7 stays because ther is no other like terms

Put these together in the final answer: 30x^3 + 9x² + 32x - 7

Hope this helps!

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The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

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Answer:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let X the random variable that represent the compressive strength of concrete of a population, and for this case we know the distribution for X is given by:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

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