Answer:
dA/dt = 31 in²/ sec
Step-by-step explanation:
The area of the triangle is:
A(t) = (1/2)*b*h where b is the base and h the height
Differentiation on both sides of the equation we obtain
dA/dt = (1/2)* db/dt * h + (1/2)* dh/dt * b (1)
db/dt = 3 in/sec
dh/dt = 2 n/sec
b = 10 in
h = 14 in
By substitution in (1)
dA/dt = 0,5* 3*14 + 0,5* 2*10
dA/dt = 21 in² /sec + 10 in²/sc
dA/dt = 31 in²/ sec
Is there more to the question?
No it does not. :) hope this helps
The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
Answer:
-9
Step-by-step explanation:
You have to plug 8 into the formula for x. f(8) = -2(8)+7 = -16+7 = -9