AABC is dilated by a factor of į to produce AA'B'C'.
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In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)
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