Okay so form a right angle triangle and the angle of that is 65 as it is right angle so 90 - 25= 65. label the sides like the pic below.
we have the hypothenuse as well as the angle and we are trying to find the o(opposite side)
o/h =sin
sin 65=23/h
sin 65 = 23/x
23/sin 65=x
x=25.4
how high the kite is above ground is :
= 25.4 +1.2
=26.6
I think it’s either a or c
Finding the inverse function:
We are given a function y = f(x). To find the inverse function, we exchange x with y in the original function, and then isolate y.
So
We are given the function:

So

Changing x with y

Now, we have to isolate y. So

We can apply the fifth root to both sides. So:
![\sqrt[5]{(y+7)^5}=\sqrt[5]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28y%2B7%29%5E5%7D%3D%5Csqrt%5B5%5D%7Bx%7D)
![y+7=\sqrt[5]{x}](https://tex.z-dn.net/?f=y%2B7%3D%5Csqrt%5B5%5D%7Bx%7D)
A.) Mark is correct as every increase in x of 2 equals a y increase of 4
your stupid........................................................................