Answer:
Lines c and b, f and d (option b)
Step-by-step explanation:
To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -
Option 1:
Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.
Option 2:
All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.
Option 3:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Option 4:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range
sub 2 for x
y=2(2)+1
y=4+1
y=5
sub 5 for x
y=2(5)+1
y=10+1
y=11
so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}
You know the triangle has a base of 6 meters, and that the formula to find the area of a triangle is 1/2bh or one-half of the base times the height. So, you would plug in 9 meters squared=one half of six times h, or 9m^2=1/2(6)*(h). In simplifying this, you would get 3h=9m^2. Divide both sides by three and get h=3. Hope this helps, and if you need any further explanations, please let me know!
Answer:
Number 7: 40%
Number 8: 75%
Step-by-step explanation: Hope i helped mate
