Answer:
From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. From a <u>graph</u>, the y-intercept will not be <u>zero</u>. From an equation, it will have the form, y = mx + b where b is <u>≠ 0</u>.
Step-by-step explanation:
- From a <u>table</u>, for an ordered pair (0, y), <em>y</em> will not be <u>zero</u>. If there is not a constant rate of change in the data displayed in a table, then the table represents a nonlinear nonproportional relationship.
- From a <u>graph</u>, the y-intercept will not be <u>zero</u>. This means that it doesn't contain or go through the origin.
- From an equation, it will have the form, y = mx + b where b is <u>≠ 0.</u> (not equal to zero). If an equation is not a linear equation, it represents a nonproportional relationship. A <u>linear equation</u> of the form y = mx + b may represent either a <em>proportional</em> (b = 0) or <em>nonproportional</em> (b ≠ 0) relationship. Therefore, when b ≠ 0, the relationship between <em>x</em> and <em>y</em> is <u>nonproportional</u>.
Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are

. We can write these sequentially as

where

.
So the integral is approximately

Recall that



so our sum becomes

Answer:
see below
Step-by-step explanation:
3t+1> 3t + 2
Subtract 3t from each side
1>2
This is never true so there is no solution
Since the variable terms are the same, we only have to look at the constants
Answer:
<h2>5 + 3w + 3 - w = 2w + 8</h2>
Step-by-step explanation:
