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GarryVolchara [31]
3 years ago
11

Parallelogram ABCD is dilated to form parallelogram EFGH. Side AB is proportional to side EF. What corresponding side is proport

ional to segment AD? Type the answer in the box below. (2 points)
Mathematics
1 answer:
NemiM [27]3 years ago
4 0
EH is proportional to AD.
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Your electric bill has been as follows for the past six months:
kakasveta [241]

You want to find the monthly average over the past 6 months.


July: $78.56

August: $30.21

September: $81.20

October: $79.08

November: $66.18

December: $100.75


Add all of these up

(July) $78.56

(August) $30.21

(September) $81.20

(October) $79.08

(November) $66.18

(December) + $100.75

----------------------------------------------

(Total cost) $435.88


There are 6 months you are calculating for, therefore divide the total (combined) cost of 6 months with the total number of months (in this case, 6)


$435.88 (total cost of 6 months) ÷ 6 (months)


The average cost per month of over the past 6 months is $72.66.

4 0
3 years ago
Read 2 more answers
Someone help me with this
Alex

Answer:

y=7.5x, y=9.25x, y=6x

Step-by-step explanation:

on the first table we have for 2 tikets $ 15 so the price for one ticket (also known as unit price) is 15/2= $ 7.5

the equation for the price of ticket must be

y= 7.5 x (where y is price you pay for x number of tikets)

on the second table you can pick that you have $37 for 4 tikets so unit price is 37/4= $9.25 per one ticket

y=9.25x

last table $12 for 2 tikets so for one ticket is 12/2=$6

y=6x

7 0
3 years ago
Read 2 more answers
Factor the expression below:<br><br> 17x –34
abruzzese [7]

Answer:

Step-by-step explanation:

17(x-2)

8 0
2 years ago
Read 2 more answers
63 first-year teachers and 27 experienced teachers attended a school staff meeting. What percentage of the teachers in the meeti
nexus9112 [7]

Answer: 70%

Step-by-step explanation:

Step 1:

Total number of teachers = 63 + 27

                                            =  90

Step 2:

The percentage of the teachers in the meeting were first-year teachers:

(63 ÷ 90) × 100 = 70%

4 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
3 years ago
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