1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly_w [17]
3 years ago
10

PLEASE HELP ME WITH THIS !

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

I believe they all have y-intersects at the origin.  From the looks of it, D and E are the same expression. I'm not sure if that is a typo or not.

You might be interested in
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
I need help on this one I have the image attached
mart [117]

Answer:

x = 40

Step-by-step explanation:

The ADF is 90 degrees so the CAF will also be 90

So you do

( x + 15 ) + 90 + 35 = 180

x + 15 + 90 + 35 - 90 = 180 -90

x + 15 + 35 = 90

x + 15 + 35 - 35 = 90 - 35

x + 15 = 55

x + 15 - 15 = 55 - 15

x = 40

4 0
3 years ago
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 42 and σ = 5.5.
alexandr1967 [171]

Answer:

a)P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

b) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(42,25.5)  

Where \mu=42 and \sigma=5.5

And we want this probability:

P( X

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

8 0
2 years ago
The sum of a rational number and an irrational number
vitfil [10]
What are you asking?
7 0
3 years ago
How do I solve this? can someone please help? thank you! y=3x+4 y=x-2 ​
Alecsey [184]

Answer:

Step-by-step explanation:

y = 3x+4 and y = x-2

3x+4 = x-2

2x+4 = -2

2x = -6

x = -3

y = -3 -2 = -5

8 0
3 years ago
Other questions:
  • What is 304,001 in word form and expanded form
    8·1 answer
  • Explain how to find 4 times 754 using two different methods
    15·2 answers
  • HELP! WILL GET 30 POINTS!
    9·2 answers
  • A bag contains 126 buttons. Some have two holes and the rest have four holes there are 8 two holes buttons for every four holes
    11·1 answer
  • Please help me solve this question. Thank you​
    6·1 answer
  • Someone please help me with this answer please it’s times and I need help real answers please
    12·1 answer
  • PLEASE HELP!!! The ratio of footballs to soccer balls at a sporting goods store is 5 to 3. if the store has 100 footballs in sto
    7·2 answers
  • David used exactly 8 cups of flour to make 6 loaves of bread. How many loaves of bread can he make with 12 cups of flour?
    7·1 answer
  • What is the value of x in the equation 5x+ 3 = 4x?<br> A.-3<br> B.- 1/3<br> C.1/3<br> D.3
    9·2 answers
  • The Question is in the picture because I could not type it out correctly for some reason.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!