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Roman55 [17]
2 years ago
7

What is 29 over 40 as a percentage

Mathematics
1 answer:
liberstina [14]2 years ago
5 0
Google is good for this, all you have to do is type in the question like that and it should work :)
But the answer is 72.5% I do believe
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Taye recruits two people to be election campaign volunteers. The next week he ask each of those volunteers to recruit two more c
jeka94

Using a geometric sequence, it is found that:

a) For the first 5 weeks, the numbers are: 2, 4, 8, 16, 32

b) Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

For this problem, on the first week there are 2 people, and since each new people involve two more, the common ratio is of 2, hence the parameters for the geometric sequence are:

a_1 = 2, q = 2

Hence the number of people after n weeks is:

a_n = 2 \times 2^{n - 1}

For the first 5 weeks, the numbers are:

  • a_1 = 2 \times 2^{1 - 1} = 2
  • a_2 = 2 \times 2^{2 - 1} = 4
  • a_3 = 2 \times 2^{3 - 1} = 8
  • a_4 = 2 \times 2^{4 - 1} = 16
  • a_5 = 2 \times 2^{5 - 1} = 32

There will be 150 volunteers when a_n = 150, hence:

2 \times 2^{n - 1} = 150

2^{n-1} = 75

\frac{2^n}{2} = 75

2^n = 150

n = 7...

The above is because 2^7 = 128 and 2^8 = 256, and 128 < 150 < 256.

Hence some of the volunteers can stop recruiting new volunteers during the 7th week.

More can be learned about geometric sequences at brainly.com/question/11847927

#SPJ1

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SERIOUSLY NEED HELP QUICK! The table shows the total cost for different numbers of jackets.
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To find three consecutive odd integers that have a sum of 63
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Figure EFGHK as shown below is to be transformed to figure E′F′G′H′K′ using the rule
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Answer:

  (a)  (4, 8)

Step-by-step explanation:

Apply the transformation rule to the coordinates of point H.

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  H(-4, 3) → H'(-4 +8, 3 +5) = H'(4, 8)

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