Answer:
(8,-2)
Explanation:
you reflect it over the x-axis
6. If 55% of the selling price is markup, the remainder (45%) is the cost. Gaitan can pay up to 45% of 489.50 = $220.28.
7. If 52% of the selling price is markup, the remainder (48%) is the cost. 48% of the selling price is $38.87.
... 0.48 × selling price = cost
... selling price = cost/0.48 = $38.87/0.48 = $80.98
8. If 40% of the selling price is markup, the remainder (60%) is the cost, $12.95.
... 0.60 × selling price = $12.95
... selling price = $12.95/0.60 = $21.58
9. If 35% of the selling price is markup, the remainder (65%) is the cost.
... 0.65 × $24.00/dz = $15.60/dz
10. If 60% of the selling price is markup, the remainder (40%) is the cost. Veronica can pay up to 40% of $600.00 = $240 for the jacket.
Answer:
2+2= 4
Step-by-step explanation:
just have a scenario like : you have two apples and your friend brings two more apples when you count them all, there are four apple
345,000
300,000+40,000+5,000
<span>Three hundred forty-five thousand
Hope I helped!!</span>
Answer:
Area of the garden:
![\begin{equation*} 398.93\text{ ft}^2 \end{equation*}](https://tex.z-dn.net/?f=%5Cbegin%7Bequation%2A%7D%20398.93%5Ctext%7B%20ft%7D%5E2%20%5Cend%7Bequation%2A%7D)
Explanation:
Given the below parameters;
Length of the rectangle(l) = 23 ft
Width of the rectangle(w) = 14 ft
Value of pi = 3.14
Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.
The radius(r) of the semicircle will now be;
![r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B14%7D%7B2%7D%3D7%5Ctext%7B%20ft%7D)
Let's now go ahead and determine the area of the semicircle using the below formula;
![A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2](https://tex.z-dn.net/?f=A_%7Bsc%7D%3D%5Cfrac%7B%5Cpi%20r%5E2%7D%7B2%7D%3D%5Cfrac%7B3.14%2A%5Cleft%287%5Cright%29%5E2%7D%7B2%7D%3D%5Cfrac%7B3.14%2A49%7D%7B2%7D%3D%5Cfrac%7B153.86%7D%7B2%7D%3D76.93%5Ctext%7B%20ft%7D%5E2)
Let's also determine the area of the rectangle;
![A_r=l*w=23*14=322\text{ ft}^2](https://tex.z-dn.net/?f=A_r%3Dl%2Aw%3D23%2A14%3D322%5Ctext%7B%20ft%7D%5E2)
We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;
![\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20Area%5Ctext%7B%20of%20the%20garden%20%3D%20Area%20of%20semi%20circle%20%2B%20Area%20of%20rectangle%20%7D%20%5C%5C%20%3D76.93%2B322%20%5C%5C%20%3D398.93%5Ctext%7B%20ft%7D%5E2%20%5Cend%7Bgathered%7D)
Therefore, the area of the garden is 398.93 ft^2