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olga2289 [7]
3 years ago
13

Find the value of x (2x) (5x +15)

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>5</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>

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25 − (8 − 4) ÷ 6 • 3=what plzzzz answer!<br> Will mark Brainliest!!!!
serg [7]
25 - (8-4) /6 *3 = 25 - 2 / 6 * 3
=25-1
=24 #


“/”= divide
“*”= multiply
4 0
3 years ago
Read 2 more answers
Please help me on this
malfutka [58]

Answer:

the answer 64!! but its asking for the product using an exponent so 4 to the third power, or 4 cubed.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASEEE HELP MEEEE<br><br>NO LINKSSS
Artemon [7]

Answer:

\huge\boxed{(2,\ 3);\ (-1,\ 6)}

Step-by-step explanation:

f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right

substitute (1) to (2):

x^2-2x+3=-x+5     add x to both sides

x^2-2x+x+3=-x+x+5

x^2-x+3=5        subtract 5 from both sides

x^2-x+3-5=5-5

x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}

substitute the values of x to (2):

x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}

3 0
3 years ago
Can you please help please please help me with this question is so hard and i will give you a Brainiest please
mrs_skeptik [129]

Question 1 :

x ≤ 4

Question 2:

i think its 40-5

7 0
3 years ago
Determine, to one decimal place, the length, width &amp; height of the rectangular prism that would have the greatest volume, wi
Leya [2.2K]

Answer:

The length = The width = The height  ≈ 5.8 cm

Step-by-step explanation:

The volume of a rectangular pyramid, V = l × w × h

The surface area of the pyramid = 2 × l × h + 2 × w × h + 2 × l × w = 200

∴  l × h + w × h + l × w = 200/2 = 100

We have that the maximum volume is given when the length, width, and height are equal and one length is not a fraction of the other. Therefore, we get;

At maximum volume, l = w = h

∴ l × h + w × h + l × w = 3·l² = 100

l² = 100/3

l = 10/√3

Therefore, the volume, v = l³ = (10/√3)³

The length = The width = The height = 10/√3 cm ≈ 5.8 cm

7 0
3 years ago
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