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kogti [31]
3 years ago
11

12 less than a number is the same as 6, deceased by 8 times the number. Find the number

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
12-x•8 if this helps
You might be interested in
Find all zeros x^3+2x^2+4x+21
dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

\frac{x^3+2x^2+4x+21}{x+3} = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± \sqrt{1-28} ) / 2 = (1 ± 3i\sqrt{3} ) / 2

x = \frac{1}{2} ± \frac{3i\sqrt{3} }{2}

zeros are x = - 3, x = \frac{1}{2} ±\frac{3i\sqrt{3} }{2}


5 0
3 years ago
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
15. Which answer choice contains all the factors of 10? A. 1, 10 B. 1, 2, 5, 10 C. 1, 2, 5 D. 2, 5
nikitadnepr [17]
B. 1, 2, 5, 10 (To feel space)
7 0
3 years ago
Read 2 more answers
Square root of 129 is greater than, less than or equal to 95/8?​
Tanzania [10]

√129 is less than \frac{95}{8}.

\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}

Let us first solve for √129.

➝\:\sqrt{129}

➝\:11.3578

Now,

➝\: \frac{95}{8}

➝\:11.875

Clearly,

➵\:11.3578 < 11.875

➵\: \sqrt{129}  <  \frac{95}{8}

Hence, √129 is less than \frac{95}{8}.

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}

5 0
3 years ago
2. Write a two-column proof.
alina1380 [7]

Answer:

Step-by-step explanation:

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

also  have no idea what I am doing half/half

5 0
2 years ago
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