We can see that the difference is 8 so we can write:

Answer:
ohlkkkk
Step-by-step explanation:
but give your questions first
Use PEMDAS
figure out everything inside the parentheses first, you still have to do PEMDAS inside of the parentheses also.
I will attach an image of how I got the first answer -7,867, sorry if my handwriting is sorta sloppy
Answer:
a) 
b) 
c) 
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are

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
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
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
<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1

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
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
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
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
Check the picture below.
the ladder is 26ft, the roof is 24ft above, so the ladderis 2ft longer than needed, if you move the ladder 10 feet away, will it give 24 or more? well, you know already.