When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of pemdas and to make sure that we take each step carefully.

We first would (first) simplify the following:

$(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . . . . \\ \\ x^7 \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \ multiplied \ by \ 2^1 = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{ (2^4*3x^1^0y^5)}}$

7 0

3 years ago

3 divide by what number equals 5

marysya [2.9K]

First write the equation
3/n = 5

Multiply both sides by n
3/n * n = 5 * n

Simplify
3 = 5 * n

Divide both sides by 5
3/5 = 5 * n/5

Simplify
3/5 = n

Divide
0.6 = n

So 3/0.6 = 5

4 0

4 years ago

X-y=3 X+2y=-6 Solve using substitution

Tresset [83]

X-y=3=>x=3+y
X+2y=-6
=========
3+y+2y=-6
3+3y=-6
3y=-6-3
3y=-9
y=-3

X+2y=-6
X+2(-3)=-6
X-6=-6
X=0

3 0

3 years ago