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3 years ago

I need help! it's for math !!!!!

Mathematics

2 answers:

lara [203]3 years ago

7 0

The answer is 200 every 10 hours, and divide them by 10 to get $20 every hour. Hope this helps!

BaLLatris [955]3 years ago

3 0

Hello kind human!

1220 + 200 is 1420. 1420 + 200 is 1620. Get it? So the correct answer here is 200

ANSWER: 200

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~Taehyungoppa

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5 miles is 8km. Convert 68km to miles

german

Answer: It should be 42.5 since 68 divided by 8 times 5 equal that

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2 years ago

Denise spent $56.48 at the grocery store while Michael spent $74.06. How much more money did Michael spendthan Denise?A.$17.58B.

ZanzabumX [31]

We will use the equation 74.06-56.48=? To find the change in prices, aka how much more money was spent. That equals 17.58. So A, Michael spent $17.58 more than Denise.

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3 years ago

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PLEASE HELP!!!! IT'S NOT B A. 1/4 B. 1 C. 4 D. None of the above

konstantin123 [22]

Answer:

YOUR ANWSER IS C

Step-by-step explanation:

HOPE THIS HELPED

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3 years ago

Estimate what is 130% of 20. Show work please! I need the right answer!

aksik [14]

26 would 130% of 26%.

20 would be 100% of itself leading us to X being 130%.
That brings us to two equations of 20=100% and x=130%
20/x=100%/130%

20/x=100/130
(20/x)*x=(100/130)*x
20=0.769230769231*x
26/0.769230769231=x
26=x therefor x=26

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4 years ago

Read 2 more answers

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

$D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13$

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0

3 years ago