Answer:
Lines c and b, f and d (option b)
Step-by-step explanation:
To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -
Option 1:
Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.
Option 2:
All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.
Option 3:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Option 4:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Answer:
-1
Step-by-step explanation:
For a line joining two points (x1, y1) and (x2, y2), it's slope is given as:

Here, the two points are (-1, 6) and (2, 3) in place of (x1, y1) and (x2, y2).
Solving for slope:




Hence, the slope of the line joining the given points is <u>-1.</u>
Log₄(y+2) = 3, transform it into exponent form:
(y+2) = 4³
y+2 = 64
y= 62
Answer:
B. 25
Step-by-step explanation:
10+6=16
if it is proportional, then it would be 25 to get 15.