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elena55 [62]
3 years ago
15

Could someone help me with this word problem? I have no idea how to solve it. Also, please don't give me the answer.

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0
He spent 5/6 of his life in america. 
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What is the 8th term of this sequence 1, -1/2, 1/4, -1/8
shtirl [24]

Answer:

-1/128

Step-by-step explanation:

1,-1/2,1/4,-1/8,1/16,-1/32,1/64,-1/128

3 0
3 years ago
Solve for x.<br>-4x - 76 &lt; -52<br>​
Roman55 [17]

First you add 76 to get

-4x<24

And Then you divide by -4 and sincr its a negative you flip the sign to get

x>-6

That might be wrong Idk

4 0
2 years ago
A quadratic equation that can be written as the difference of squares has...
quester [9]

Answer: C two solutions

Step-by-step explanation:  

The Difference of Two Squares theorem says that any time an equation may be written as a difference between squares A² - B² = 0 it may be rewritten as two products, the sum and difference of the square roots (A + B) (A - B)

Hope this helped :)

6 0
2 years ago
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Examples of properties communative, associative, and identity?
BlackZzzverrR [31]

Answer:

Communative: 12 x 5= 5 x 12 Associative: (5) + 6 = (8) + 3 Identity: 5 x 1= 5

Step-by-step explanation:

3 0
3 years ago
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What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
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