3 years ago

Plz help me get the right answer to these

2 answers:

8 0

Step-by-step explanation:

$(-7b^5+42b^4)\dib7b=\dfrac{-7b^5}{7b}+\dfrac{42b^4}{7b}=-b^4+6b^3$

4 0

- $b^{4}$ + 6 $b^{3}$

divide each term on the numerator by 7b

= - 7 $b^{5}$ / 7b + 42 $b^{4}$ / 7b

= - $b^{4}$ + 6 $b^{3}$

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