Question

Plz help me get the right answer to these

Answer 1

Step-by-step explanation:

$(-7b^5+42b^4)\dib7b=\dfrac{-7b^5}{7b}+\dfrac{42b^4}{7b}=-b^4+6b^3$

Answer 2

- $b^{4}$ + 6$b^{3}$

divide each term on the numerator by 7b

= - 7$b^{5}$ / 7b + 42$b^{4}$ / 7b

= - $b^{4}$ + 6$b^{3}$