Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
I’m going to say multiply both sides by a which gives you:
a^2-ab-a=2
If not give me a call
Answer:
C I think
Step-by-step explanation:
The first problem is true because with multiplication it doesn't matter which order it is in.
The second problem is false because you will get a different quotient depending on which numbers are on which side of the equation.
Answer:
Step-by-step explanation:
Length = L.
Width = 2L-3.
A = L * W = 170.
L * (2L-3) = 170.
2L^2 - 3L - 170 = 0,
L = (-B +- Sqrt(B^2-4AC))/2A.
L = (3 +- Sqrt(9 + 1360))/4,
L = (3 +- 37)/4 = 0.75 +- 9.25 = 10, and -8.5. In.
Use positive value: L = 10 In.
