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3 years ago

Plz help me get the right answer to these

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Step-by-step explanation:

$(-7b^5+42b^4)\dib7b=\dfrac{-7b^5}{7b}+\dfrac{42b^4}{7b}=-b^4+6b^3$

Citrus2011 [14]3 years ago

4 0

- $b^{4}$ + 6 $b^{3}$

divide each term on the numerator by 7b

= - 7 $b^{5}$ / 7b + 42 $b^{4}$ / 7b

= - $b^{4}$ + 6 $b^{3}$

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What is the answer?????

Gnesinka [82]

Answer:

Step-by-step explanation:

m+2/2 = 1/2

m=0.5

2m+4=5 is the correct answer

3 0

3 years ago

1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

s344n2d4d5 [400]

Answer:

a). Mileage for carA= $\frac{2}{x}$ , and mileage for carB= $\frac{ 3x+2}{x(x+1)}$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

= $\frac{5x+4}{2x(x+1)}[tex]mil/gal$

Step-by-step explanation:

It is given that the distance traveled by car $A=2x+2=2(x+1)$

And distance traveled by car $B= 3x+2$

We know the mileage is mile/gallon,

a).So mileage of car $A= \frac{distance traveled by car A}{gallos of fuel used}$

$=\frac{2x+2}{x^2 +x}\\ =\frac{2(x+1)}{x(x+1)} \\=\frac{2}{x}mil/gal$

Similarly , the mileage for car $B= \frac{distance traveled by car A}{gallons of fuel used}$

$=\frac{3x+2}{x^2+x} \\=\frac{3x+2}{x(x+1)}$ $mil/gal$

b).total mileage for both is similar to average of them= $\frac{(mileageA + mileageB)}{2}$

$=\frac{2x+2}{x(x+1)}+\frac{3x+2}{x(x+1)}\\ =\frac{2x+2+3x+2}{x(x+1)}\\=\frac{5x+4}{x(x+1)}mil/gal$

Now divide by 2 for total(average) mileage.

$\frac{\frac{5x+4}{x(x+1)} }{2}\\ =\frac{5x+4}{2x(x+1)} mil/gal$ .

Thus those are the answers.

4 0

3 years ago

For what value of the number k is the following function differentiable at x=2

d1i1m1o1n [39]

Answer:

For f(x) to be differentiable at 2, k = 5.

Step-by-step explanation:

For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.

For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.

Now,

f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.

As h tends to 0, lim (5 – 2h) = 5

Also

f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h

As h tends to 0, lim (5 + 3h) = 5.

So, for f(2) to be continuous k = 5

7 0

3 years ago

A dolphin jumped up out of the water and back into the water in a parabolic path. (H) height (t) seconds . H=-8(t-0.5)^2+2 . How

tigry1 [53]

Answer:

4 seconds

Step-by-step explanation:

using the vertex formula of a quadratic,

$a(x-h)^{2} + k$ , where (h,k) is the vertex

$h = -8(t-0.5)^{2}+2$ h is height and t is time in seconds

the vertex (maximum height) of the dolphin is (h,k) or (0.5, 2)

Height of 1/2

time of 2 seconds

it will take 2 additional seconds to reach the water again.

this can also be solved using quadratic equation, but since it was already set up in vertex form, i'd use that.

4 0

3 years ago

the price of a technology stock was $9.53 yesterday. Today, the price rose to $9.66. Find the percentage increase. Round your an

galben [10]

So, 9.66 - 9.53 will then be 0.13, so if we take 9.66 to be the 100%, what is 0.13 off of it in percentage then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
9.66&100\\
0.13&p
\end{array}\implies \cfrac{9.66}{0.13}=\cfrac{100}{p}\implies p=\cfrac{0.13\cdot 100}{9.66}$

6 0

3 years ago