Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main()
{
// Declare integer variable n which serves as the quotient.
int n;
// Prompt to enter any number
cout<<"Enter any integer number: ";
cin>>n;
// Check for divisors using the iteration below
for(int I = 1; I<= n; I++)
{
// Check if current digit is a valid divisor
if(n%I == 0)
{
// Print all divisors
cout<<I<<" ";
}
}
return 0;
}
above
dgczjklcxhvzkojcvrhyujnhb
explanation:
Answer:
You need to explain the entire network layout first.
Explanation:
Bringing on new IT Staff can be time consuming. But depending on the possession you need to explain to them how the domain lay out is.
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
Flexibility and open-mindedness
being quick to adapt to technology changes
having a positive attitude
taking initiative to solve problems
