Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)

and

-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.

Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.

5 0

3 years ago

Evaluate this exponential expression 7 • (6+2)^2 - 3^2=

Lelu [443]

Answer: 441

Step-by-step explanation:

$7*(6+2)^2-3^2$