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Alina [70]
3 years ago
5

PLEASEEE HALPPPPPP >.<

Mathematics
1 answer:
butalik [34]3 years ago
3 0
A. 21 miles

You divide 2 into 32 and get 16, then you add 16 plus 14 subtract 9 and get 21
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Please help me with this
sesenic [268]
Ok so the average is 50

average of x number of things is
(add value of all things)/x=average

4 test scores needed
so divide by 4
3 test scores ar known
average is 50
x= missing score

(43+48+42+x)/4=50
times 4 both sides
133+x=200
minus 133 both sides
x=67

a score of 67 is needed
5 0
3 years ago
28 &lt; 4v <br> solve for v <br> pls help
DedPeter [7]

Answer:

v = 7

Step-by-step explanation:

Divide both sides by 4 to isolate v

28/4 = 4v/4

v = 7

5 0
2 years ago
What are the next three numbers 14,34,54,74,94....
Helen [10]

Each term is (the previous term increased by 20).

The next 3 terms are  <em>114,  134,  154 .</em>


7 0
3 years ago
Read 2 more answers
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If h(x)=\frac{f(x)}{g(x)}, then:

h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}

Since in our case we want the derivative of h(x) at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}

which, by replacing with the given numerical values:

f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3

becomes:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0

3 0
3 years ago
What is 25% off $1099.00
Alecsey [184]
25/100 x 1099=$274.75
Hope I helped.

4 0
3 years ago
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