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Alina [70]
4 years ago
5

PLEASEEE HALPPPPPP >.<

Mathematics
1 answer:
butalik [34]4 years ago
3 0
A. 21 miles

You divide 2 into 32 and get 16, then you add 16 plus 14 subtract 9 and get 21
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S varies inversely as G. If S is 8 when G is 1.5​, find S when G is 3. ​a) Write the variation. ​b) Find S when G is 3.
ss7ja [257]

Step-by-step explanation:

a.

s \:  =  \frac{k}{g}

8 =  \frac{k}{1.5}

k \:  = 1.5 \times 8 = 12

s =  \frac{12}{g}

b.

s =  \frac{12}{3}

s = 4

4 0
3 years ago
The figure shows a person estimating the height of a tree by looking at the
FrozenT [24]

Answer:

The proportion that can be used to estimate the height of the tree is option;

A. \dfrac{h}{12} = \dfrac{6}{5}

Step-by-step explanation:

The given parameters in the question are;

The medium through which the person looks at the top of the tree = A mirror

The angle formed by the person and the tree with the ground = Right angles = 90°

The distance of the person from the mirror, d₁ = 5 ft.

The height of the person, h₁ = 6 ft.

The distance of the tree from the mirror, d₂ = 12 ft.

The angle formed by the incident light from the tree on the mirror, θ₁ = The angle of the reflected light from the mirror to the person, θ₂

Let 'A', 'B', 'M', 'T', and 'R' represent the location of the point at the top of the person's head, the location of the point at the person's feet, the location of the mirror, the location of the top of the tree and the location of the root collar of the tree, we have;

TR in ΔMRT = The height of the tree = h, and right triangles ΔABM and ΔMRT are similar

The corresponding legs are;

The height of the person and the height of the tree, which are AB = 6 ft. and TR = h, respectively

The distances of the person and the tree from the mirror, which are BM = 5 ft. and MR = 12 ft. respectively

∴ The angle formed by the incident light from the tree on the mirror, θ₁ = ∠TMR

The angle of the reflected light from the mirror to the person, θ₂ = ∠AMB

Given that θ₁ = θ₂, we have;

tan(θ₁) = tan(θ₂)

∴ tan(∠TMR) = tan(∠AMB)

tan\angle X = \dfrac{Opposite \ leg \ length \ to \ reference \ angle}{Adjacent \ leg \ length \ to \ reference \ angle}

tan(\angle TMR) = \dfrac{TR}{MR} = \dfrac{h}{12}

tan(\angle AMB) = \dfrac{AB}{BM} = \dfrac{6}{5}

From tan(∠TMR) = tan(∠AMB), we have;

\dfrac{h}{12} = \dfrac{6}{5}

\therefore h = \dfrac{6 \, ft.}{5 \, ft.} \times 12 \, ft. = 14.4 \, ft.

The height of the tree, h = 14.4 ft.

Therefore, from the proportion \dfrac{h}{12} = \dfrac{6}{5} the height of the tree can be estimated.

3 0
3 years ago
explain how the relationship between the mean and median provides information about the symmetry or skewness of the data's distr
Klio2033 [76]

Answer:

mean gives you the average of the information, median gives the perfect number. brainliest please

4 0
2 years ago
PLEASE HELP QUICK Suppose a particle is moving along the x-axis. The position, measured in feet, of the particle can be modeled
Romashka-Z-Leto [24]

When 'x' is zero, 'y' is -9.

That simply means that when time began ... when the starter

fired his pistol and the clock started running ... the particle

was 9 units 'before' zero, in the region of negative location.


By the way ... the way the question is written is enough to confuse

anyone, and I hope that hasn't contributed to your trouble with it.


If the particle is moving along the x-axis, then 'x' is its location,

and the time in seconds is something else. Say 't' for example.

Also, if it's moving along the x-axis, then 'y' is always zero.


The position of the particle is modeled by an equation like


X = 3t² - 12t - 9 .


'X' is the position of the particle, and 't' is the time in seconds.

7 0
4 years ago
A company is designing a new cylindrical water
Nutka1998 [239]

Answer:

21

Step-by-step explanation:

To find the area of a cylinder you mutliply radius by height.

r*h = 162

If we know the height is 7.7, substitute it for <em>h.</em>

r*7.7 = 162.

Or:

162 / 7.7

Which gives you 21.03, or 21.

8 0
3 years ago
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