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3 years ago

What effect does the court surface have on the height that the basketball bounces?”

Biology

2 answers:

NikAS [45]3 years ago

6 0

Answer:

The type of surface a basketball collides will have an effect on the height of the bounce.

When a basketball collides with a surface, some energy is absorbed by the surface. Hard surfaces like concrete, absorbs only a little energy, which gives the ball more energy to bounce. Soft surfaces, like a carpeted floor for instance, absorbs more energy and as a result, the ball does not bounce as high.

The more energy the surface can absorb, the less energy will be left in the

Contact [7]3 years ago

4 0

The type of surface a basketball collides will have an effect on the height of the bounce.

When a basketball collides with a surface, some energy is absorbed by the surface. Hard surfaces like concrete, absorbs only a little energy, which gives the ball more energy to bounce. Soft surfaces, like a carpeted floor for instance, absorbs more energy and as a result, the ball does not bounce as high.

The more energy the surface can absorb, the less energy will be left in the ball, which decreases the height of its bounce.

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Explanation:

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Homozygous individuals have two copies of the same allele for a gene. Homozygous dominant individuals carry two copies of the dominant allele, while homozygous recessive individuals carry two copies of the recessive allele.

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DNA sets contain genes that may have different forms named alleles. DNA, which is the genotype, is transcribed into mRNA and later translated into amino acids which are connected together by rRNA to form proteins which constitute the phenotype of an organism. DNA sequence mutations form new allles, impacting the resulting mRNA, and thus the encoded protein. Within species, there may be adaptation, along with genetic drift, preferential breeding, and natural selection.

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$p^{2} + 2pq +q^{2} = 1$ ....(eqn i)

where...

p represents the dominant allele frequency

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q^2 = the genotypic frequency of the homozygous recessive

p^2= the genotypic frequency of the homozygous dominant

2pq= frequency of the heterozygous genotype

and simply p+q= 1 ...(eqn ii)

The allelic freq. of r is denoted by q and the allelic frequency, R is denoted by p...

The total number of individuals= 32+ 68= 100

Thus q= √ $q^{2}$ = homozygous recessive individuals (white flowers)

Since there are 32 white flowering plants , freq rr= 32÷ 100= 0.32

...thus $q^{2}$ =0.32

and q= √ $q^{2}$ = √0.32= 0.566

Learn more about mutations at brainly.com/question/4602376

Learn more about DNA and RNA at brainly.com/question/2416343?source=aid8411316

#LearnWithBrainly

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