Placing the equations under the correct solution, we get
x = 3 x ≠ 3
-14x = -42 -5 + x = -9

x -5 = -2
<h3>Solving Linear Equations </h3>
From the question, we are to place the equations under the correct solution
To do this, we will solve the equations one after the other
x = -42/-14
x = 3
x = -9 + 5
x = -4
∴ x ≠ 3



x = 3


x = 3
x = 3 × 9
x = 27
∴ x ≠ 3
x = -2 + 5
x = 3
Hence, placing the equations under the correct solution, we get
x = 3 x ≠ 3
-14x = -42 -5 + x = -9

x -5 = -2
Learn more on Solving linear equations here: brainly.com/question/13204213
#SPJ1
Answer:
<u>Distributive Property</u>
Step-by-step explanation (if you were to show the steps):
(x+2)(y+z) <u>(first expression)</u>
xy + xz + 2y + 2z <u>(Distributive Property of Multiplication)</u>
yx + 2y + zx + 2z <u>(use the Commutative Property of Addition and Commutative Property of Multiplication to group xy (also known as yx) and 2y together, and to group xz (also known as zx) and 2z together)</u>
y(x + 2) + z(x + 2) <u>(use factoring to get the rewritten expression at the end)</u>
Answer:
(-2,-6)
-2
Step-by-step explanation:
To get the vertex take the number that's in the parathenses with the x and flip it's sign (in this case to a negative) which means we have
-2
this is the x coordinate of the vertex.
Next take the number that's being subtracted (or added) on the outside and leave that as is (-6)
This is the y coordinate
which means we have (-2,-6)
the axis of symmetry is just the x coordinate of the graph
which is -2
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²