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Vika [28.1K]
3 years ago
6

The diameter of a circle is 10 miles what is the radius

Mathematics
2 answers:
love history [14]3 years ago
8 0
The radius is 5 because the diameter is 10 so you divide 10 by 2 and get 5
nexus9112 [7]3 years ago
3 0

Answer:

5

Step-by-step explanation:

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Write a sine function that has a midline of 2, an amplitude of 4 and a period of 11.
svetoff [14.1K]

Answer:

y = 4 sin(2π/11 x) + 2

Step-by-step explanation:

y = A sin(2π/T x + B) + C

where A is the amplitude,

T is the period,

B is the phase shift,

and C is the midline.

A = 4, T = 11, and C = 2.  We'll assume B = 0.

y = 4 sin(2π/11 x) + 2

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2 years ago
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7 0
3 years ago
Solve the inequality.
timofeeve [1]

Answer:

x < -6

Step-by-step explanation:

18 + x < 12

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4 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
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Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
2 years ago
Calculate the product 78.93 times 32.45
Alona [7]

Answer:

2561.2785

Step-by-step explanation:

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2 years ago
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