3 years ago

Some one plzz help this is my third time asking this question

Mathematics

2 answers:

eduard3 years ago

6 0

Answer:

everyone clickin cuz its a lot of points

Step-by-step explanation:

lys-0071 [83]3 years ago

6 0

Answer:

I don't really know it but if you use socratic I will find the answer for you

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A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

denis-greek [22]

Let $x$ be the distance from the left wall to the laser source and $y$ the distance form the right wall to the laser source.

We can use the cosine trigonometric function in the smaller triangle to relate the adjacent side of the angle and the hypotenuse; then we can solve for $x$ :
$cos( \alpha )= \frac{adjacent.side}{hypotenuse}$
$cos(60)= \frac{x}{40}$
$x=40cos(60)$
$x=20m$

We can use the tangent trigonometric function in the larger triangle to relate the opposite side of the angle and its adjacent side; then we can solve for $y$ :
$tan( \alpha )= \frac{opposite.side}{adjacent.side}$
$tan(45)= \frac{80}{y}$
$y= \frac{80}{tan(45)}$
$y=80m$

Now we can add both distances:
$20m+80m=100m$

We can conclude that <span>the distance between the walls is 100 m.</span>