√75 = √(5²×3) = √5² √3 = 5√3 = 8.66
√48 = √(4²×3) = √4² √3 = 4√3 = 6.93
√12 = √(2²×3) = √2² √3 = 2√3 = 3.46
√125 = √(5²×3) = √5² √3 = 5√3 = 11.18
√28 = √(2²×7) = √2² √7 = 2√7 = 5.29
Answer:
The raw score for his exam grade is 99.69.
Step-by-step explanation:
Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.
To find : What is the raw score for his exam grade?
Solution :
The formula use to find the z-score is
Where, z=1.67 is the z-score
is the means
is the standard deviation
x is the raw score for his exam grade
Substitute the values,
Therefore, the raw score for his exam grade is 99.69.
i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Answer:
The bottom graph is the graph of that equation
