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Vadim26 [7]
3 years ago
11

NEED ANSWER NOW.. PLZ HELP NEED CORRECT ANSWERS!!!!WILL MARK BRAINLIEST!!

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

1. Equal

2. Not equal.

Step-by-step explanation:

1.     -2 * -0.16 = -0.32

      0.16 * (-2) =  -0.32    EQUAL


2.    0.4 / (-3) = - 0.1333...

       -3 / 0.4 =   -7.5  Not equal

       



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How to find vertex form with vertex: (3,6) and y intercept: 2
bekas [8.4K]

Answer:

<h3>              f(x) = - ⁴/₉(x - 3)² + 6</h3>

Step-by-step explanation:

The vertex form of  the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

So for vertex (3, 6) it will be:

f(x) = a(x - 3)² + 6

<u>y intercept: 2</u> means  f(0) = 2

f(0) = a(0 - 3)² + 6

2 = a(-3)² + 6

2 -6 = 9a + 6 -6

-4 = 9a

a = ⁻⁴/₉

Therefore:

The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is

                             <u>f(x) = - ⁴/₉(x - 3)² + 6</u>

5 0
3 years ago
***TOP SAYS BAND AND PLAY INSTRUMENT AND NOT IN BAND AND PLAY INSTRUMENT***** A survey asked 50 students if they play an instrum
Stels [109]
I am pretty sure the answer is B
5 0
3 years ago
What is the square route of pi
vagabundo [1.1K]
It is simply would be: √π

= √3.14

= 1.7728

In short, Your Answer would be: 1.7728

Hope this helps!
7 0
3 years ago
Read 2 more answers
Find the outer perimeter of this figure.
stira [4]

Answer:

61.90

Step-by-step explanation:

12.2+14+14+6=46.2

of semi circle

circumference of semi circle = \pid

\pix10 = 10\pi

semi circle so divide by 2 = 5\pi

5\pi = 15.7

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3 0
2 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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