Answer:
At least 75% of these commuting times are between 30 and 110 minutes
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by 
.
In this question:
Mean of 70 minutes, standard deviation of 20 minutes.
Since nothing is known about the distribution, we use Chebyshev's Theorem.
What percentage of these commuting times are between 30 and 110 minutes
30 = 70 - 2*20
110 = 70 + 2*20
THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes
<span>A ball is thrown at a 30 degree angle above the horizontal with a speed of 10 ft/s. After 0.50s the horizontal component of it's velocity will be the same. In a projectile motion the horizontal component of the velocity is said to be constant. Therefore, it will be equal to the initial velocity.</span>
The answer is 0.51111111111111111 (It goes on for infinity).
Mean: Add up the numbers and divide the sum by the number of values in the set.
6 + 9 + 2 + 4 + 3 + 6 + 5 = 35
35 / 7 = 5
Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.
2, 3, 4, 5, 6, 6, 9
^
So, the median average is 5.
Mode: What number appears the most frequently?
The mode of the set is 6 because it appears twice.
Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.
9 - 2 = 7
The range is 7.
Answer:
number of ways = 720
Step-by-step explanation:
The number of ways six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then
number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720
Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.
