<span>a = 1/2 x b x h
h = 3b
so 1/2 x b x 3b = (1/2)(3b^2) = 150
(150 x 2)/3 = b^2
100 = b^2
b = square root of 100 = 10
h = 3b = 3 x 10 = 30</span>
Answer:
the line crosses the parabola at (-2,4) and (3,9)
Step-by-step explanation:
y=x^2
y=x+6
set them equal to each other
x^2=x+6, now set it equal to zero
x^2-x-6=0, now find the root
(x+2)(x-3)=0, the x=-2, and x=3; now substitute into any of the equation to find the points where graphs intercept
at x= -2, y=(-2)^2=4, so one point is (-2,4)
at x=3, y=(3)^2=9, so other point is (3,9)
the line crosses the parabola at (-2,4) and (3,9)
Answer:
Step-by-step explanation:
given that f(a) = K
we have the options of
f(K) = a
f ⁻¹ (K) = a
f ⁻¹ (a) = K
Where f ⁻¹ denotes an inverse function.
If f(a) = K, then its reciprocate, f ⁻¹ (K) = a
because it is essentially undoing the original equation
2 7/8 + 2 3/8= 4 10/8, which equals 5 2/8, which is also equal to 5 1/4
Answer:
8...I want these points lol
Step-by-step explanation:
